#Pascal triangle and the expanding the binomial using it
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Make any question, I need to clarify it in my head
so, what specifically are you asking?
their relationship, or an actual expansion problem?
perfect
(4x+6y)^4
if expanding we can represent it as $\sum_{k=0}^{4} \binom{4}{k}(4x)^k\cdot (6y)^{4-k}$
so calculate each term and add them together
no don’t do that 😅
;( | 追放された興奮
like, let me explain what he taught me
this is what i was taught
and what i learnt from, in videos
its this kinda problem
what i have presented is a simplified and much less messy form.
Are you sure?
yes.
Sure, ill go with it
all you do is calculate each term
do i put this in my calc?
so for k=1, this would be 4*(4x)(6y)^3
eh, i don’t know if it will work
im confused, Where to we begin from, where do we break it down
bro idk, im hella confused with this example, can you work it out and ill see if i understand?
alright
so we have (6y)^4+4(4x)(6y)^3+6(4x)^2(6y)^2+4(4x)^3(6y)+(4x)^4
okay okay
why did you start with
y first though?
i thought it was x
x, xy, xy, xy, y
or am i buggin
it really doesn’t matter
Sure I guess, Okay continue
mhm
alright, try one on your own
but u didnt, simplify them
you can simplify it in your own
ah, I see
this is CONFUSING DAMN
I understand it, my problem is
I dont know, where to
multiply first
and in what order to go through
like
4(4x)(6y)^3
order doesn’t matter
where do my multiply first
oh like that
I know order doesnt matter
im saying, so i can
have a tiny rule to make it simpler
well we know 6^3=216 right
okay
like wdym
when i do math i always try to find something to simplify things more
u js told me
6 powered by 3 is 216
now ill know, to start from there
yeah
then move onto the others
i guess so?
as a rule
yes
alright so
like
4(4x)(6y)^3
where do i start from
and where do i end at
u said
6^3
technically im starting from the right
so, continue
its 216
so u start from
right to left
6^3
then u move onto the 4's
and u times it with what u had
and u got ur answer
yes
or just use calculator if you are allowed
,calc 44216
Result:
3456
yep
brb
@coarse lodge
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