#Trigonometric Ratios of Acute Angles

34 messages · Page 1 of 1 (latest)

flint rover
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Hi, can someone help me? I really don't know how to solve it

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floral ivyBOT
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flint rover
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kk

hollow star
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you can find cos(A) and cos(B) if you set the hypotenuse equal to 1

flint rover
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something like that?

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molten relic
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you want to find the value of just cosA and cosB

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which you can do by setting the hypotenuse to 1

flint rover
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Could it end up as a system of two equations?

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I'm very bad at this

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lol

molten relic
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think about it geometrically, not algebraically

flint rover
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dang

molten relic
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another way you can go about doing this is
what is cosA in terms of side lengths?

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like $\tan \alpha = \frac{MN}{NO}$ smthn like this

nova hazelBOT
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!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!

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flint rover
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oh

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I don't understand the problem, honestly

molten relic
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but you do understand simple trig ratios, right?

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all we need to do rn

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is just find the side length ratios of this right triangle

flint rover
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I don't understand because of the letters haha

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I get confused too quickly

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So the adjacent side, which we will call AC, will be equal to cos A?

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So I will do the same with the others, right?

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look

hollow star
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that works

flint rover
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oh okay okay

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I will continue

north wharf
flint rover
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+close