I need help with algebra (I'm cooked)

[umbral wedge]

Got a exam in about 2 days yet I don't understand algebra nor functions

Just need help whenever you available then private dm me

[cyan quarry]

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[dapper plinth]

(no dms allowed in server) but i can help with any topics you're struggling if you provide examples

[umbral wedge]

Okay no problem so when can we do this?

[dapper plinth]

like, the whole day?

you post problems i guide you through them

[umbral wedge]

Seems very reliable

Is discord calls allowed through this server?

I'm new so bare with me

[dapper plinth]

yes but i am not avaliable for those

and i am about to eat

[umbral wedge]

Okay so whenever you available throughout the day just let me know when you could call

Because I can't just read shi and get it like that if you get me

[dapper plinth]

i cant call the entire day

[umbral wedge]

Okay bro

Then just send me whatever you need to

[snow edge]

U got any material to review?

[umbral wedge]

Nah just you just gotta send me basically work sheets of the stuff in every possible way the questions could be asked upon the topic

I'll do the studying myself since someone else helped me with the multiplying adding simplifying and subtracting part

[dapper plinth]

.

could you send your own problems?

[umbral wedge]

Sure

basically that

[dapper plinth]

okay we can start from 1.1.1

so x^2+5x-6=0

we can factor this

into some form (x+a)(x-b)=0

[umbral wedge]

okay

usually in my country for that first question we use the quadratic formula

[dapper plinth]

uh, no.

you can do that for 1.1.2

not for this

[umbral wedge]

the answer for the first one is +1 and -6

[dapper plinth]

yes

[umbral wedge]

check is bro

[dapper plinth]

wait

yes

[umbral wedge]

im telling you bro im right

lol

[dapper plinth]

it works, but it isn't the most efficient method.

[umbral wedge]

yea not always but yea

n e ways

[dapper plinth]

use quad formula for 1.1.2

and now we can move on to 1.1.3

[umbral wedge]

question 1.1.2 i=the answer is -0.88 and 0.68

now question three is where i struggled

[dapper plinth]

okay

so imagine graph of function

like this

[umbral wedge]

basically we solving for x

[dapper plinth]

actually wait

expand LHS first

add 3

and re-factor it

so it is =>0

[umbral wedge]

then we come to the point of 2xsquared + 5x -3

using distyributive law

then i think......

make a bracket since x is a common for both numbers

[dapper plinth]

add 3 both soides

[umbral wedge]

thren you will come to the point of x(2x+5)

[dapper plinth]

cause 2x^2+5x-3>3

oh yeah ur right

!

[umbral wedge]

then x will equal to -5 over 2 or x will equal to 0

i think thats the answer

[dapper plinth]

thats the solution answer

not the inequality answer

[terse otter]

@umbral wedge

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