#how to do this. i know that integration will be for rational is x^2/2, irrational will be x^3/3
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your reasoning?
$\abs{\int_{[0,2]}f(x)\diff x-\int_{[0,2]}x^2\diff x}\leq \sum_{n=1}^{\infty}M\text{Vol}(r_n-2^{-n+\beta}, r_n+2^{-n+\beta})$
Cofailure
for all $\beta\in\bN$
Cofailure
and large enough M
This is possible due to the rationals being countable and hence too scarce to make a difference in a sense as compared to the rest of [0,2]
this is $\leq M\cdot \mu([0,2]\cap\bQ)=M\cdot 0$ as $\beta\to 0$
where mu is the lebesgue outer measure, in this case 0
Cofailure
Here $\text{Vol}(L)=b-a$ for open intervals $L=(a, b)\subset\bR$
Cofailure
what do you mean?
Alg alg integration kar liya
is there something wrong in my process? It has been a long time since I did this so let me know
√2,√3 irrational
Matlab?
what
Process m wrong ni h
alg alg bhi kar sakte ho
Lekin bhai ap jaise explain karte vo begginer k liye sahi thodi rahega
ek hi scene he
yes it'll suffice for anyone who has learnt riemann integration
it's your fault for not studying definitions
I just read again lower and upper riemann definition
If $\mu(E)=0$ then $\int_{X\setminus E} f=\int_{X} f $
Cofailure
Measures aren't really needed here but it makes explaining it easier
this is the main idea at the end here
specially for countable E
we can remove smaller and smaller intervals centered around the element of E to show than E has negligible effect
here's another example
what do you not understand in the above process?
this one
Absolutely
alpha+beta and M volume?
hum toh base × height karte the bas
Area of small rectangle
I explained it later on scroll down
Also they ask for the upper riemann integral
@slate flint are you there?
In the upper riemann integral, U(f) = inf U(f, P), in the summation for U(f, P)s we are taking the supremum of the function over the intervals in said partitions P and as they become finer and finer we can use the fact than x>=x^2 on [0,1] and x=<x^2 on [1,2] to get the upper integral
not very rigorous but this points towards ||D|| as the answer
I was looking for youtube
In the partition the irrational and rational will be seperated?
use the definition of the upper Riemann integral with the fact than rationals are dense in R
that's over the whole interval
we work in arbitrarily small ones when evaluating U(f)
HERE f(x)=x when x is rational and x^2 when x is irrational
yes
+close