#Help on Calculus, limits questions.
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you can use the graph in q3 to think about q1
I kind of understand why I got q3 wrong but how can it not be e?
e also makes sense right?
RHS of x=3 DNE
and thats because theres no line on the RHS?
the function ends at x=3
so for q1, i still cant understand why its wrong
i dunno bro
look at x=-1 on q3
ok yeah theres a point at y=2 and y=1 , so is B on q1 wrong because the limit as x approaches c doesnt necessarily have to equal L? and I think A could be wrong because in the limit it doesnt say that f(x) is defined at c or else the limit would be lim x->C f(x) = f(c) right? if that isnt it I think it could just be wrong because f(x) would be defined at L for sure because C might be a hole or something. idk why C isnt wrong tho
-1 is again a case against C
for a function to be continous it cant have a discontinuity in it and -1 is a discontinuity?
yup and just to clarify L is a real number meaning it cant be a hole right?
the limit would still exist but f(x) would not be defined which like breaks the first step in proving that something is continous right?
but theres the case right after thats like
if its not continuous but the LH and RH limits are equal the limit is that
yeah but the limit can still exist but it just cant be continuous right?
mhm
alr
15 you have to lhopital it i think
i aint even learn that bruh 😭
ion think thats gonna be on the test im gon ignore tha
okay nvm i lied you can just like
do the normal bounding thing
where you ignore the constants
not gonna hold u man but idk what the normal bounding thing is because on god she only talked about it like once
and never spoke about it again
for 16?
because as x gets really large
the other values dont really mean much
I knew that sqrt5x^2 u wanted to make it similar to so you can cancel out the x
x's
oh
bro
i lowk get that one now
indeterminate form?
I thought u had to multiply by the conjugate but like cant you just plug in 0 and figure out it doesnt exist
u only like simplify and shit when its 0/0
idk what the form name is tbhy
yup
a/0 is asymptote form
there is a trap where
if the left and right are equal
this usually happens if the demon is squared
then the limit exists
oh alr