If ax^3 + bx + c when a and b are not equal to zero has a factor in form x^2 + px + 1, show that a^2 - c^2 = ab
#polynomial
desert plank
timid crowBOT
If ax^3 + bx + c when a and b are not equal to zero has a factor in form x^2 + p...
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desert plank
I solved it by doing ax^3 + bx + c = (x^2 + px + 1)(dx+e) and expanding
But before I did it my teacher said it can be done by long division in terms of a and b
Idk what to do using his method wondering if u guys have any idea
potent geode
If ax^3 + bx + c when a and b are not equal to zero has a factor in form x^2 + p...
depressed cubic moment lmao
anyways
Yes you can use long division here
oh hell no this looks ugly asl 💀
oh i see
maybe do long division of dx+e on ax^3+bx+c
doing it on x^2+px+1 doesn't work out well
actually, im kinda lost here 
torn viper
doing it on x^2+px+1 doesn't work out well
it’s alright
i think you get ap^2 + b - a = 0 and c+ap = 0
potent geode
i think you get ap^2 + b - a = 0 and c+ap = 0
oh so from here
torn viper
c^2 = a^2p^2 and substitute that into the first equation
potent geode
c^2 = a^2p^2 and substitute that into the first equation
yeah yeah i know
but thx ig?
desert plank
d=a and e=c btw
desert plank
(x^2 + px + 1)(ax+c) instead of the one I put before if it’s simpler
torn viper
did you still need help