#I know how to approach this question but I'm having trouble finding what the sequences actually are
76 messages · Page 1 of 1 (latest)
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close - Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules. If there is a conflict amongst multiple helpers feel free to ping “Helper Mod”
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
01 23 45 67 89
10 32 54 76 98
90 81 72 63 54
a few to start you off
how do you know what they are
it has been sent here before
you would’ve come across it
yeah
there are four with 0~4 in one digit and 5~9 in the other
should we start with the amount of possibilities?
another four with one digit being purely odd and the other even
arithmetic is increasing by the same amount each time right
i have not found others
i dont understand how you know what the sequences are
what do you mean?
for the tens digit at least
how do you come up with these like is the a rule
i have found a rule that gives me some of the sequences, but i cannot prove it gives all of them
you can only have 1 increasing or 0,2,4,6,8 and 1,3,5,7,9 for tens digit
the rule is that if both the tens digit and the ones digit are in arithmetic progression, then the two-digit numbers will be
for strictly increasing
this gives me 8 numbers
10 32 54 76 98
oh yeah that too
so there are 8 sequences
i would perhaps elaborate on why something like 0 2 4 7 9 fails
eh
but it isnt arithmetic is it
not for the tens digit, but a reason should be provided for why the whole number cannot be in AP
because it doesnt increase by same amount each time?
a “carrying over” rule, correct?
ok so these numbers are the tens digits
yes; very annoying
lol, this is what makes problems like these 10x harder
i still dont get how we find sequences which use all number 0 to 9
i have a faint idea, but it probably will not work
we can define the first number of the sequence to be 10a+b
and the common difference d
what so second is 10a+b+d
yes
but this doesnt help with using all numbers 0 to 9
yeah
we can choose a d such that all the numbers are used
let’s go with the case d=9 since it is the easiest to show
we can start with a=0 and b=9
wait i think i just got an idea
d either has to be a multiple of 3 greater than 6 or a multiple of 11
!
why
uses 10 twice
yes ok
why
look at what happens when d<=8
hypothetically, 08 16 24 32 40
we are guaranteeing, with d=>8, that the tens digit is not repeating
tens digit doesn’t repeat
maybe geq then
+close