#Co-ordinate geometry help
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Do you remember the general form of the equation of the circle?
yeah
What is it?
Well, that's only if it's centered at the origin.
(x-h)^2 + (y-p)^2 = r^2
Right! Now, let's transform it a bit.
Open both brackets and collect similar terms (as in, quadratic terms, linear terms and constant term).
As I said, collect similar terms.
There are five kinds of terms here: x^2, y^2, x, y and constant.
Well, more or less.
Now, notice how this can be written in the following form:
x^2 + y^2 + Ax + By + C = 0
Can you see why that's true?
Yes
Nice.
Now, notice how if you substitute coordinates of a point into that equation, you'll get a linear equation in A, B, C.
So, if you substitute three different pairs of coordinates, you get a system of equations.
i get 3 simultaneous equations?
Yeah. A system of three linear equations.
So, you can find the coefficients from it.
Well, yeah, solving linear systems isn't very exciting. But oh well, what can we do ๐
No.
Work with the equation we've obtained: x^2 + y^2 + Ax + By + C = 0.
Otherwise the equations you'll get won't be linear, and it's harder to solve those.
ohhh yeah