can anyone help me with this question

[thorny wedge]

The value of x^2 - 6x + 13 can never be less than :-

1)5 ; 2)4 ; 3)6 4)13

[quaint ledge]

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[hidden basin]

try to put this equation into vertex form

i.e. $(x-a)^2+c$

[wide void]

;(

[hidden basin]

wherer the point $(a,c)$ is the minimum of the graph of $x^2-6x+13$

[wide void]

;(

[thorny wedge]

ah yes i got x coordiate 4 so thats the ans but is there a simpler way to solve it tho??

[hidden basin]

x coordinate is not 4

[hidden basin]

there is no simpler way unless you want less rigor (which i dont recommend)

[thorny wedge]

mb y

i said x on accident

[thorny wedge]

ah for such questions its better to plot graph? but i only have like 1m to solve ig

[hidden basin]

ig

[thorny wedge]

ah alr thanks so much 🙂

[hidden basin]

yw

+close to close

[thorny wedge]

k

+close