#How is 1+x^2 = 1/(1+x^2)
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negative sign should have turned into a positive sign
where particularly?
since ln(x) = -ln(1/x)
it still doesnt match no?
i tried solving integration of arc tanx w/ two methods
both of them lead me to diff ends
want me to share full context?
that would be nice
a sec
@sudden swifthere u go
i basically tried methods to solve inverse functions
and got diff answers
@trim dune
hmhm??
there will be an (extra -)
Log x^a=alogx
this^?
i’m reading your second solution
your first one looks fine but i could still be wrong
yeah
A minus sign
sintdt=-dp
yeah -sintdt=dp
Derivative of cos is -sin
@sudden swift ???
i believe the mistake was made in the previous step
but if you take - to other side its -dp
So outside it will be plus not minus @trim dune
let me go thru
where you write t*tan(t) + int(tan(t)dt)
pls wait a sec
@doraemon?
reverse product should be a - there?
the - was placed out the front
but i don’t think it should ever have been there
yeah it was meant to be t*tamt - int(tant.dt)
this should account for the sign error?
@trim dune integration of tan x is -log cos x
So minus minus =plus
But u wrote minus
In next step
Why?
let me show what i was doing
Nah u got it now right?
wait
what…
Today in my exam I had to integrate sin^-1 root x 
oh dear
That was just a part I'll send the whole ques in general chat
@corazon sorry for this
oh i see
needed a negative inside of int()
but let it go out
and then integrated thinking it was inside the int()
let me solve it
@sudden swift @sudden swift thank you guys for helping in my dumb quesn.
@trim dune has given 1 rep to @lavish vale @graceful vector
im sorry to waste your time
on the contrary, you stopped me from wasting it
then?
yessir?
i would have done something much less productive instead
Do the ques in math discussion channel
ah i see
yeah im going back to study now sorry
+close