complex numbers

[summer bough]

Can someone please explain what I’ve done wrong? For c

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[summer bough]

The reason I did pi/2 +pik was because of the i

Since i^2 is real

So like z^n(conjz) would be purely imaginary but when you multiply it with i it becomes real

[sacred robin]

$z^n\bar z$ is purely imaginary.

[scenic tartan]

waffle

[summer bough]

Yeah but wouldn’t it become real when it’s multiplied by i

[sacred robin]

that's the point

[summer bough]

Yeah that’s what I did

isnt it +πn

[sacred robin]

nvm that doesnt work

[sacred robin]

$z^n\bar z=z^{n-1}\cdot z\bar z=z^{n-1}\cdot\underbrace{\abs{z}^2}_{\text{Purely Real}}$ is purely imaginary. Therefore $z^{n-1}$ is purely real.

[scenic tartan]

waffle

[sacred robin]

@summer bough can you continue?

[summer bough]

hi yeahh I figured it out