#continuities

73 messages · Page 1 of 1 (latest)

hybrid cedar
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I missed a day now I’m lost pls help

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ornate basaltBOT
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green falcon
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but never fear i am here!

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which parts you need hep with

hybrid cedar
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covid

hybrid cedar
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i dont remember A that well tho so idk if thats right

green falcon
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augh

green falcon
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b is just finding where x^2+7x+10=0 because that makes the function n/0 which makes it undefined

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so factor and solve it

hybrid cedar
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oh alr

green falcon
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yea

hybrid cedar
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thanksss

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im gonna work through the question ill lyk if i need anymore help

green falcon
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yw!

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okay

hybrid cedar
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@green falcon how do i do e

green falcon
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augh

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aight i won’t complete the explanation

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i’ll finish it tmrw

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,ti

gusty pagodaBOT
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The current time for exiled_hype is 09:49 PM (EDT) on Sun, 15/09/2024.

green falcon
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hmmmmm

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gn

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i’m gonna think about that

hybrid cedar
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mkay

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thx again

green falcon
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@hybrid cedar ik i said gn but i just got an idea

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try making a piecewise function with f(x)

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now gn

alpine wedge
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is help still required?

green falcon
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@hybrid cedar wanna close the post?

tribal flax
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so critical points here will be -5 and -2

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c) part is calculating the limit of a function when x goes to positve infinity and then do the same when x goes to negative infinity.
d) part is taking (left and right) limit of a function when x -> critical point (in this case, those are -5 and -2) and here you should get infinities. If you get a finite number asymptote doesn't exist. But I might be wrong on my last take

alpine wedge
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i think it’s also noteworthy that the answer to a) is incorrect

tribal flax
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mb

tribal flax
alpine wedge
tribal flax
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yeah

tribal flax
# hybrid cedar I missed a day now I’m lost pls help

for part e you would need to know what a piecewise function is. In other words, g(x) will contain f(x) for it's domain (so entire R excluding -5 and -2) and then you can make some new variable a that will be a value for x=-2. After that solve the limit of f(x) at x->-2 and that what you get will be the value of variable a.

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I will give you a hint for this one: You will get indeterminate form for the limit so you will have to use something like lhopital

alpine wedge
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part e) will use the answer to part b), which does not require l’hopital’s

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it would suffice to factorize numerator and denominator of the fraction given and cancel out the factor of (x+2)

tribal flax
alpine wedge
tribal flax
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cool way to do it as well

alpine wedge
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$\lim_{x \to -2}\frac{x^2+5x+6}{x^2+7x+10}$ will give an indeterminate result, as will $\lim_{x \to -2} \frac{(x+2)(x+3)}{(x+2)(x+5)}$, but $\lim_{x \to -2} \frac{x+3}{x+5}$ is defined

gusty pagodaBOT
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Micabo

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alpine wedge
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(please latex)

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good enough

tribal flax
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but Lhopital is literally life hack

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I love lhopital

alpine wedge
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i can see that

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it’s just unnecessary here

tribal flax
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agreed

green falcon
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anyway looks like op isn't responding

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i dont have perms to close the post

alpine wedge
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give it time

tribal flax
alpine wedge
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not OP

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just the whole situation

tribal flax
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lmfao

alpine wedge
hybrid cedar
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+close