#Quick question on span (linear algebra)
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Do you mean whether B keeps the span the same?
If so, no. Consider a linear subspace L = ℒ({1, 1}, {2, 2}), so basically just ℒ({1, 1}). Apply a rotation matrix to it. Clearly, it won't be the same subspace.
Or did you mean that the image of the span is the same as the span of the images? If so, I think that's true... Though, I'm not 100% sure.
The question may require some clarification here
For instance, in a vector space of dimension 1, any linear transformation is a homothety
so in that sense, no matter what the linear transformation is, the resultants will stay in that line
likewise in a vector space of dimension 0
but in higher dimensions, there is no reason why a linear transformation should generally preserve a (strict) subspace
So if the span(v1,v2) where it is a linear line that you can graph it as so. But when you set Ax = b, where you graph b, it shows that it doesn't lie on the same line that of span(v1,v2).
bear with me because im like really early into linear algebra
first of all, if v1 and v2 are nonzero collinear vectors, then span(v1, v2)=span(v1)
second, I do not think you clarified the points I stated before
if your entire vector space is just a flat line, it is trivially true that any linear map is just a multiplication by a constant
in which case it still maps any element on the line, back on the line
so if im talking about the span(v1) i know that its a line, but the line can exist anywhere on the plane and that theres no "strict subspace" for it as you said before?
well, my point is whether the entire vector space you're considering was a line, a plane, a 3D space or anything bigger
no one says your vector spaces have to be of dimension 2
which is what I wanted to clarify with you
okay so, if the vector space is just 2 dimensions is what youre asking?
What is the dimension of your ambient vector space?
in 2d
so that is one q answered
So yes then Darpinger's answer applies
There is generally no reason for linear maps to preserve lines
see rotations for example
what happens if it was another dimensions like R^3
same thing
there is no reason for any linear transformation to preserve any line
in the eventuality there is one such line that is stable via this transformation, this line is an eigenspace of said transformation
okay what if i were to say to graph the span of the columns of the matrix. Would the span still be non-preservable on linear maps?
now that's an entirely different question
the span of multiple vectors may be a vector space of dimension bigger than 1
so it may not be a line anymore
in particular, for an invertible matrix, the columns span the entire vector space
so it would be hard to say that the span isn't preserved, it is trivially preserved
okay