help hw

[slow tree]

write 3^n / 9^n-1 as a power of 3

[fallow bison]

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[runic pond]

Note that 9 = 3^2.

[slow tree]

ok

waut]

i think ik how

[small ibex]

also, $a^{(x)*b}=b^{xb}$

[peak turret]

Anon #HumansDontMatter

[slow tree]

i got to

3^n / 3 ^2n-2

[small ibex]

note that a^x/ a^y = a^(x-y)

[slow tree]

so i subtract (n) - (2n-2)

[small ibex]

yes

[slow tree]

that gives -n-2?

[small ibex]

what is -(2n-2)

we can also rewrite this as -1* (2n-2)

[slow tree]

idk

it says the answer is 3^2-2n

but i dont get how it get there

[small ibex]

hmm, do you know the distributive property of multiplication

[slow tree]

i dont think so

[small ibex]

so, it basically is

$a*(b+c) = ab + ac$

[peak turret]

Anon #HumansDontMatter

[slow tree]

yh ik that

[small ibex]

thats the property

[small ibex]

in this case, a= -1, b= 2n and c= -2

can you find the value

@slow tree

[slow tree]

wait

i got to 3^n / 3^2n-2

[small ibex]

yes

[slow tree]

do i now just subtract the power from numerator to dominator

3^2-n?

[small ibex]

yes

[slow tree]

ok

thanks

[small ibex]

thats correct

[slow tree]

wait i got one more question sorry

[small ibex]

close with +close @slow tree

oh okay

[slow tree]

ur acc the goat btw

work out the exact value of n

9^1/3 x 3^n = 27^ 4/5

[small ibex]

note that 9= 3^2

[slow tree]

k

[small ibex]

and 27= 3^3

try doing it now

[slow tree]

so its

3^ 2/3 x 3^n = 3^12/5

[small ibex]

yes

[plain elk]

The problem is

\frac{3^{n}}{9^{n-1}}
``` right?

[slow tree]

now common dominator

[peak turret]

M

\frac{3^{n}}{9^{n-1}}
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.49 \frac{3^{n}}{9^{n-1}}
                          
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.

LaTeX Font Info:    Trying to load font information for OT1+lmr on input line 4
9.
(/usr/local/texlive/2023/texmf-dist/tex/latex/lm/ot1lmr.fd```

[slow tree]

yh

[plain elk]

Close enough

[slow tree]

is it 26/15

[small ibex]

note that $a^{b}* a^{c}= a^{b+c}$

[peak turret]

Anon #HumansDontMatter

[small ibex]

yes

you got it

[slow tree]

tysm bro

[small ibex]

np

[slow tree]

how long u beendoing maths

[small ibex]

,calc 12/5 - 2/3

[peak turret]

Result:

1.7333333333333

[small ibex]

Im in 8th grade

[slow tree]

oh nice same

+close