#logarithmic
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you can just sub the answer in to check lol
it usually results in complex outputs but yea it could be negative
i mean for integers it works fine, for all reals it gets messy
Are you sure?
the problem is when you’re doing like
through basic definition we want the base a raised to some power to be equal to b
so if a is negative and as long as c is like an integer we don’t get confused on if it’s positive or negative or whatever
i actually dunno how they define that
,w log_(1/3) 81
,w log_(-1/3)81
@worthy dagger
turn this into an exponential equation
(-1/3)^x = 81
(-3)^-x = 3^4
now times both sides by (-3)^x
(-3)^-x * (-3)^x = 3^4 * (-3)^x
oh
I don't think this works
I guess you can consider different cases where x is odd, even and a fraction
and verify your solution
@clever coral
+close