#Need Help with this
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@west palm
You probably want to bring the other logarithm to the left and write everything as one logarithm
Do you know any trig identity that has sinxcosx, or maybe 2sinxcosx?
yeah, sin 2x but the thing is if it is allowed to multiply 2 inside modulus (LHS) and RHS
Ah, I see what you mean. Yes it is allowed because 2 is a positive number.
I think
yeah, but if it was a negative number then it would be a different case
Well actually you don't need to multiply by 2 for now
You can just say sinxcosx = sin(2x)/2
so yes both resulted in same answers
So, how many solutions are there
For x € [0,2π)
I am so sorry questiont was incomplete
but solutions will be 8
I think so