#How to calculate the integral in the question
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The integral of a total differential over a closed curve, assuming the function is continuous inside the region bounded by the curve, is 0.
The physical analogy would be potential or potential energy.
Ah, yeah, that's true, it isn't a total differential.
As for how to check it - you can find the rotor of this field. If it's 0 (vector), then it's conservative and the differential is total.
Ahh, wait.
Sorry, I didn't pay close enough attention. This is a second differential.
Then I don't quite understand how we're integrating this over a closed curve. It is a surface integral, not a line integral.
There is no parametrization given
Given a 2-form of your manifold $\eta$ and $X:R\to M$ is a 2-segment (rectangular patch of the manifold), then $\int_X\eta=\int_R X^\ast(\eta)$
Omegabet_
you're just integrating the push forward/pull back (whatever upper astericks is again lol) of the form over the euclidean region
Hm... Yeah, seems like I haven't learned this, sorry.
I’m confused
I assume you're taking differential geometry?
Then you're using atypical notation
But anyway, for a 1-form $\varphi$ and a curve $\alpha$, $\int_\alpha\varphi:=\int_a^b\varphi(\alpha'(x))\dd{x}$
Omegabet_
the analogous for 2-forms and regions holds too
Seems the curve in question is not given
$\iint_R\omega:=\iint_R\omega(X_u,X_v)\dd{u}\dd{v}$, where $X$ parameterizes the region
Omegabet_
it's a loop
Would x^2+y^2=1 work
Uh how do I show for any loop
wdym
Is it enough to show it is not 0 for one loop
if you think the result isnt 0, sure
If the result is 0 how to show it is 0 for all
but it's two questions:
-
Check if $\omega$ is exact.
-
If $\omega$ were exact, how would we use that to compute integrals of it?
Omegabet_
but yeah, the notation beind used is shit lol
Is there another way to check n st dn = w exists
by definition of the differential
Isn’t the way to check is to compute the integral and check if it’s 0
Thats one way yes
integrate omega over some region and hope it isnt 0
that requires finding such a region though
alternatively you know $\dd^2{\varphi}=0$, so exact implies closed
Omegabet_
Omegabet_
You can also invoke Poincare's Lemma if you've covered it (forms defined on R^n are exact iff closed)