#Geogebra
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@pseudo hatch
alright
just wait someone will help
No need to use nested ifs.
f(x, y) = (a/b) if(x > 0 ∧ y > 0 ∧ x + y < 40, (1 + x/100)/(1 - y/100))
Apart from that, the usual approach works. Though, here it will work only if you specifically include the boundary by doing f(x, y) = (a/b) if(x >= 0 ∧ y >= 0 ∧ x + y <= 40, (1 + x/100)/(1 - y/100)).
- Find critical points in the interior, if there are any.
- Find critical points on the boundary. If it's given piecewise, also consider the boundary points between the pieces.
- Compare the values at all the critical points you've found.
how do i find critical points on the boundary?
Parametrize it. Here it's pretty easy, considering it's piecewise linear.
i dont know what parametrize or piece means
You should review parametric and piecewise functions, then.
ok, do you want to get pinged if i need help again?
Well, I check help posts here relatively frequently if I'm not busy. You can just reply to my comment, no need to specifically ping me.
btw, there are no parametrics. i used the wrong function at the start. the function without parametrics is below. will this change the problem?
What do you mean by "no parametrics"?
like no a or b, just constants
Well, that doesn't matter.
But that's not what I meant above.
The boundary of your region is described by three inequalities: x ≥ 0, y ≥ 0, x + y ≤ 40. So, we can divide it into three pieces and parametrize them as follows:
- x = 0, y = t, 0 ≤ t ≤ 40
- x = t, y = 40 - t, 0 ≤ t ≤ 40
- x = t, y = 0, 0 ≤ t ≤ 40
Note that t is unique for each case. If that confuses you, you can call the parameters by different names, like t1, t2 and t3.
what is t
Parameter.
i believe the highest point is on the boundary, could you help me find it?
Try it yourself first.
As I said above, check each piece of the boundary, then the points between the pieces.
wdym by piece, i didnt study math in english
I don't really know how to explain it in another way. And neither did I.
i found out what i wanted to find out