#euclidian

6 messages · Page 1 of 1 (latest)

marble pendant
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gcd (1407, 266) = 7
1407 = 5 x 266 + 77
266 = 3 x 77 + 35
77 = 2 x 35 + 7
35 = 5 x 7 + 0

how do i find 21 = 1407c + 266d? i know how to find it if it's the gcd but 21 isnt even in the euclidian

lament pewterBOT
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eternal hemlock
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Well with Euclid’s algorithm you can find a and b such that 1407a+266b=7 then simply multiply by 3 on each side