functions

[bitter panther]

question 3 pls

[native spear]

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[bitter panther]

I don't think you really need a translation

@hasty rose

[hasty rose]

hi

[hasty rose]

i will ask for one out of spite

translate it hehe

[bitter panther]

ok

[bitter panther]

which one

[bitter panther]

hallo

Some induction proof right?

[hasty rose]

for 3 and 4

the rest is aight

translate

[bitter panther]

i just want help with 3

not 4

3. Let p in Z and q in N*, prove f(r) = ar with a = f(1)

[hasty rose]

hah

what

[bitter panther]

what

[hasty rose]

prove it from 1 directly

[bitter panther]

how

We only need r in Q+

but how to prove f(r) = ar

[hasty rose]

ok wait lemme get on phone

[bitter panther]

okeyz

[bitter panther]

what

[hasty rose]

gluten morgan

I'm back

f(p)=qf(p/q)

as f(nx)=nf(x)

so f(p/q)=pf(1/q)

f(rp/q)=rpf(1/q)=r(pf(1/q))=rf(p/q)

you get the gist

@bitter panther

[bitter panther]

ok

wow

[bitter panther]

so?

i dont get it

[hasty rose]

get what

[bitter panther]

where tha proof

[hasty rose]

of?

[bitter panther]

f(r) = ar

[hasty rose]

@bitter panther

think, try to derive it from here

f(p/q)=f(p)/q

what can you do now?

[bitter panther]

f(p)= pf(1)

[hasty rose]

cool

that's it

[bitter panther]

but where did f(p/q)= f(p)/q come from

[hasty rose]

read my messages to figure out

[bitter panther]

oh shit

you're crazy with it thx

.close