Do I not just find the derivative of this equation, then set it to zero to find it's critical points? Then use those critical points to find the domain for when its negative or postive?
#I am so confused
winged monolith
magic monolithBOT
Do I not just find the derivative of this equation, then set it to zero to find ...
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winged monolith
yes IK
but we should create a number line and plug in when the x's make the y's negative
winged monolith
this question doesn't talk about displacemenet
we use position to find displacement
there are multiple parts to this question
main kettle
Ohk
winged monolith
this is what i was talking about
to see when the graph is going into negative direction
winged monolith
yes
main kettle
Bro actually
Velocity is already given
This f(t) was velocity
So we don't need to take the derivative
Set f(t) = 0
winged monolith
No we use derivative too see the rate of change if it's heading to the negative direction or positive direction because f'(x)=0 are the points where there's an inflection point from negative to positive
I know we set f(t)=0 but why cant we just use my way?
main kettle
Actually bro
Velocity is rate of change
And velocity is given in question
So we don't need to find rate of change