#What function is this?
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that would be standard notation, yes
sigma is one of 3! permutations on 3 elements
Sigma(1) can be 1,2 or 3 then sigma(2) is one of the two remaining elements that isn’t sigma(1) and sigma(3) is the last element remaining that isn’t sigma(1) or sigma(2) that’s what a permutation is, a bijection from {1,2,3}
To {1,2,3} in this case
And I’m guessing $(x_i)_{1 \le i \le 3}$ are the roots of the cubic
Rotor
The only thing that you need to know is that all $\sigma(i)$ are all distinct (by injectivity)
Rotor
And no, I don’t think it does matter because whichever root you choose in what order because it would be the same as permuting twice the columns each time which will not change the determinant
@coarse mesa has given 1 rep to @thin matrix @violet sphinx