help.

[prisma mauve]

help.

[snow dagger]

1. Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
2. Wait patiently for a helper to come along.
3. Once someone helps you, say thank you and close the thread with:

   +close
   

4. Feel free to nominate the person for helper of the week in #helper-nominations
5. Do not ping the mods, unless someone is breaking the rules.
6. If you're happy with the help you got here, and the server overall, you can contribute financially as well:

[obtuse lily]

ok im here to help

@prisma mauve

[prisma mauve]

ok

[obtuse lily]

ok so do you know how to calculate area of composite shapes?

[prisma mauve]

no😊

[obtuse lily]

Ok so to calculate area of composite shapes, you need to break down the specific shapes area, and than add them together

[obtuse lily]

so here, 2 shapes are in the composite shape

what are they?

[prisma mauve]

um

[obtuse lily]

so what shapes can you see here?

there's 2 shapes

[prisma mauve]

2

OH

[obtuse lily]

Yeah

wait gimme me a few mins

[prisma mauve]

triangle and square

[prisma mauve]

ok

[obtuse lily]

Yep

so do you know how to find area for triangle and square?

[prisma mauve]

no

[obtuse lily]

Ok so the formula for a triangle is
0.5xbasexhiehgt

square is lengeth x width

now solve it

[prisma mauve]

i dont get it

how am I gonna solve it

[obtuse lily]

to solve composite shape area, you need to add together fhr area of the 2 shapes

[prisma mauve]

whats the area

[obtuse lily]

...wdym?

the total area convered...

[prisma mauve]

cant u just tell me the answer

[obtuse lily]

No, I'm here to teach not just tell you the answer

@prisma mauve how old are you?

[prisma mauve]

im 14

yr 9

[obtuse lily]

Ok good

[prisma mauve]

i still dont e=get ut

get it

[obtuse lily]

Ok ok so

@prisma mauve whats the area of a rectangle?

[prisma mauve]

u mean all the numbers added up right?

[obtuse lily]

No thats perimetre. Area is when you multiply the length and width

[prisma mauve]

45

[obtuse lily]

there you go, thats the first shape done

ok now to the triangle

do you know pythagerous @prisma mauve

[prisma mauve]

no

[obtuse lily]

$ pythag is c^2=a^2+b^2

$ pythag is c^2=a^2+b^2$

fuck fuck what

[obtuse lily]

this is pythag formula

so the hypotenuse is c^2

[prisma mauve]

square 2??

[obtuse lily]

C to the power of 2

[prisma mauve]

mk

[obtuse lily]

ok so pythag is c^2=a^2+b^2

so you have c^2

@prisma mauve you also have one another length can you figure it out?

[prisma mauve]

theres another lengh?

[obtuse lily]

So to use pythagerous, you need 2 lengths.

you have the hypotenuse, which is c^2

you need another length

[prisma mauve]

theres only 9 and 15

[obtuse lily]

so you have the hypotenuse (longest side) which is 15. thats your c^2 done. Now you also have a^2, which is your 9.

so your formula is
15^2=9^2+b^2

can you solve this algrebrically?

[stone apex]

u can use EQUA on your calc if u have one.

[prisma mauve]

i do have a calc

[obtuse lily]

you shouldnt be using calc for this

dont use an calc for this

you need to do this on paper

[prisma mauve]

ok

[stone apex]

u can check with it.

[prisma mauve]

what are those mini arrows?

[stone apex]

that means c*c

^2

[obtuse lily]

that means to the power of

[obtuse lily]

no, to the power of

@daring vector how do I get latex here

$ 2^2 $

[prisma mauve]

Idk how to solve it

[daring vector]

Don’t put the space

[obtuse lily]

$2^2$

[kindred vapor]

Broken Sigma

[obtuse lily]

ight so do you know basic algrebra

[prisma mauve]

no

[stone apex]

write it on paper

[obtuse lily]

ok @prisma mauve I think you should practice basic algrebra solving skills before trying problems such as this sorry :(

anyway
$c^2=a^2+b^2
15^2=9^2+b^2
225=81+b^2
now subtract 81 from both sides
144=b^2
square root it
b=12

Learn basic algrebra and pythag before these kinda questions, trust me itll make it 10x easier$

[kindred vapor]

Broken Sigma
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[prisma mauve]

they want the answer in a decimal

[obtuse lily]

there's no decimal..

[prisma mauve]

look

[obtuse lily]

so youll just put 144+area of square

so 57.0

[prisma mauve]

is that it?

[obtuse lily]

@prisma mauve you put it as 57.0

[violet hill]

no

[obtuse lily]

Yeah

[obtuse lily]

huh

[violet hill]

you find the area of the triangle

and add it to the area of the square

[obtuse lily]

oh shit

I was so focused on pythag I forgot about that

[violet hill]

12 is just the side

[obtuse lily]

@violet hill can you help @prisma mauve

[violet hill]

@prisma mauve do you know the area of triangle formula?

[violet hill]

I can try

[prisma mauve]

no

[violet hill]

Which grade are you in?

[prisma mauve]

9

[violet hill]

do you know what are right angled triangles?

[prisma mauve]

yes

[violet hill]

so for calculating the area of a right angle triangle you multiply both the sides and divide the product by 2

so can you now tell me the area of the triangle?

did u get me @prisma mauve ?

[prisma mauve]

both sides of the triangle?

[violet hill]

yes

not the hypotenuse

the smaller sides

[prisma mauve]

theres only 1 number on the triangle

[violet hill]

you just found out the other one

using pythagoras theorem

[prisma mauve]

mhm

[violet hill]

yes, so you should now multiply both of them and divide the result by 2

[prisma mauve]

both?

[violet hill]

(9*second side which you found out)/2

[prisma mauve]

multiply 15 by 9

[violet hill]

no

the other one

which u just found out

[prisma mauve]

5?

[violet hill]

$(15^2-9^2)^(1/2)$

$(15^2-9^2)^(1/2)$

$root over (15^2-9^2)$

[kindred vapor]

CoolGeek

[violet hill]

@obtuse lily how to represent square root?

$(15^2-9^2)^1/2$

[obtuse lily]

√

[violet hill]

$√(15^2-9^2)$

[kindred vapor]

CoolGeek

$√(15^2-9^2)$
```Compilation error:```! LaTeX Error: Unicode character √ (U+221A)
               not set up for use with LaTeX.

See the LaTeX manual or LaTeX Companion for explanation.
Type  H <return>  for immediate help.
 ...                                              
                                                  
l.49 $√
         (15^2-9^2)$
You may provide a definition with
\DeclareUnicodeCharacter```

[violet hill]

it isn't working

[obtuse lily]

$√$

[kindred vapor]

Broken Sigma
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[obtuse lily]

ugh thats weird

Idk

[prisma mauve]

um

[violet hill]

$sqrt(15^2-9^2)$

@prisma mauve do you know what is a square root?

[prisma mauve]

yes

[violet hill]

then do this

$(15^2-9^2)$

[kindred vapor]

CoolGeek

[violet hill]

solve this and then find it's square root

[prisma mauve]

144

[violet hill]

that will be the unknown side

[violet hill]

what is the square root of 144?

[prisma mauve]

12

[violet hill]

so, now you have found out the unknown side

can you find the area of the triangle now?

[prisma mauve]

what do i do now

add it?

[violet hill]

(9*unknown side)/2

[prisma mauve]

huh

[violet hill]

what is the unknown side

12 right?

[prisma mauve]

yh

[violet hill]

substitute it there

[prisma mauve]

what

[violet hill]

9*12/2

solve it

that will be the area of the triangle

[prisma mauve]

whats the star btw

[violet hill]

multiplication

[prisma mauve]

54?

[violet hill]

its called an asterisk

[violet hill]

yea

now add it to the area of the square

[prisma mauve]

144??

[violet hill]

54+45

[prisma mauve]

99

[violet hill]

thats ur answer

[prisma mauve]

but it wants it as a decimal

[violet hill]

are there any options?

[prisma mauve]

no

[violet hill]

they said upto 1 decimal point

doesn't have to have decimals

[prisma mauve]

ok

[violet hill]

it can

there are some good yt channels like Math with Mr.J, try watching

[prisma mauve]

but i had the answer on paper

and it didnt work last time

[violet hill]

is it a test?

[prisma mauve]

no its homework

I put it in nd its right

[prisma mauve]

Thanks

[exotic elbow]

@prisma mauve has given 1 rep to @violet hill

[violet hill]

welcome

[prisma mauve]

do I close it now

[violet hill]

I think even Broken sigma deserves it

[violet hill]

use ".close"

[prisma mauve]

Thanks

how long is the cooldown

[violet hill]

idk

I never used it

[prisma mauve]

Thanks

@obtuse lily Thank you

.close

[earnest plover]

Unable to parse the channel name

[obtuse lily]

:)

@prisma mauve dont forget to do basic algrebra practice, its really important

[prisma mauve]

Yea lol

.close

[earnest plover]

Unable to parse the channel name

[obtuse lily]

ig the bots broken

rip

[prisma mauve]

lol, I'll just leave the thing here then

[obtuse lily]

oh its +close

@prisma mauve

[daring vector]

+close