#Can anyone help me with this?
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I don’t think it’s defined because depending if x tends from the left or right side the denominator is going to be either always 0 or always 1
$\tan(x)=x+\frac{x^{3}}{3} +o(x^{4})$
Rotor
For x approaching 0
now if x<0 you can see that around 0 tan(x)<x but if x>0 tan(x)>x
so if x tends from the left side you will get 0 for the denom and 1 if it’s from the right side
likewise depending on from which side x tends you have asymptotically sin(x)<x for x>0 and sin(x)>x for x<0
So one of both tends to 0 or 1
in the sum I mean
@dense obsidian
Mmmm, But here they didn't say anything like x is approaching from left or right
No I think I got confused i any case tan(x)/x>1
because either tan(x)>x for x>0 or tan(x)<x for x<0 so tan(x)/x>1 in any case
So the denominator tends to 1
Okk Hmhm
Yes 👍
So denominator is 1
@obsidian stirrup
Can't we say
that
when x is tending to 0
Sinx is approximately equal to x
But these espressions "Sinx/x" and x/Sinx"
are not defined at x = 0
yes we can but here its the greatest integer function so you need to see if sin(x)/x<1 or sin(x)/x>1 for x approching 0 so depending on that fact the function is going to be 0 or 1 when x >0 sin(x)<x and for x<0 sin(x)>x but in any case you have sin(x)/x<1 and x/sin(x)>1
because around 0 sin(x)=x-x^3/6 +o(x^4)
so you can conclude
Mmmm, so it's -1
well considering around 0 sin(x)/x <1 then floor(sin(x)/x)=0 for x approaching 0
and floor(x/sin(x))=1 for x approaching 0
Yes
Ok @obsidian stirrup
Thanks for your help 🙂
I understood
Umm, How to give a rep point for you?
lol
thanks
reply by thanking me if you want to give rep points
@obsidian stirrup has given 1 rep to @dense obsidian
ill do it for u
thanks @obsidian stirrup
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thanks @obsidian stirrup
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+close