#Lin alg(logic)
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just definitions
for conjunctive and disjunctive normal forms
the dnf comprises elementary conjunctions, so if the formula is true for (0,0,0) then the corresponding conjunction is (not x1 and not x2 and not x3)
for dnf you have a disjunction of 4 elementary conjunctions (because the formula is true under 4 different evaluations)
@wicked bluff
Thanks G ๐๐ฝ