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Ah the prisoner's dilemma!
If Beatrice goes for a hare, what does Alfonso get when going for a hare and what if he goes for the deer instead?
would it be that he should go for the deer?
that would be the best response right?
Why would that be the best response?
because he would get the biggest portion
Are you sure that's right?
I suggest you read the question again
ok one sec
ok so
both going for deer = payoff of 10 each
one going deer and one hare = payoff of 0 and 3
and if both go for hare = payoff 3 each
what are payoff mean?
@tender sable
Payoff is the reward expressed as a number, higher is better
oh I see
so he shouldn't go for the deer then
in that case, he should also go for the hare
I agree!
but surely just me saying that isn't worth 13 marks right
Can you explain in words why?
because he would be getting the highest payoff if he went with the hare in respct to the other option
I don't think so, you'd need to provide an argument as to why this is the case
Sounds good to me!
that's worth 13 marks?
And what if he did not know what Beatrice would do?
That's the actual prisoner's dilemma
he should still go for the hare
Hmmmmm why?
because choosing hare will always give a payoff of +3
whereas if he chooses deer
actually wait
that's a hard question
Right? That's why it is a dilemma!
I know what the optimal strategy is in this case
In game theory your opponent is someone that always chooses the "best option"
ohhh so deer then
In this case choosing the deer is beneficial to both you and the other person, whereas going for the hare is worse
The actual prisoner's dilemma is different
what is it?
here's another question too
not sure what nash equilibrium means
Nash equilibrium is about the optimal choice of a player given that the other player chooses a certain option
So the question before was the nash equilibrium for Alfonso given that Beatrice chose the hare
ohh I see
so it's the same concept but different wording?
is the nash equilibrium 3?
No the Nash equilibrium is the strategy you employ given that the other person does a certain strategy
Let's say that the other person goes for a hare. You would also go for a hare in that case, since it has the better payoff
If the other person goes for the deer you would also do so, since then the payoff is higher
so that would be 1 nash for this instance?
or do I not say how many in numbers but rather explain each strategy?
Yes you say the strategy
I believe it is something like (hare,hare) and (deer,deer)? Not sure, I'd have to look that up
ok here are the strategies:
-
if one goes for deer, then it would be optimal to also go for deer as the payoff for each is 10
-
if one goes for hare, it would also be optimal to go for hare as the payoff for each is 3
-
if one goes for deer then it would be optimal to go for hare as they will get a payoff of 10.
ohh yes, now that you say that it rings a bell
- (deer,deer)
2.(deer,hare)
3.(hare,hare)
4.(hare,deer)
I hope that's correct
Those are not the equilibria but all possible combinations of events
Because 2 and 4 don't seem to be equilibria
I see, how would I do it?
The equilibria are, given that person A chooses option a, what would be the best to do for person B
I believe there are only two optimal startegies in this case
I agree
(deer,deer) and (hare,hare)
Exactly
before that, so if I just say this, I get 13 marks?
or do I explain why too
I think you'd have to explain why too
ok ๐
I'll be back in 5mins and we can do this one
if you want
ok im back
the respective payoff would be 10?
because in this case, they would both get the maximum desired benefit
Because if you could communicate and would be bound to that that would be the best?
I find it curious that probability is not a factor in these questions
yes
so we answered all three?
Wait I want to check something
ok
The probability for the other player choosing each of the two options
Suppose that I chose to hunt the deer.
The expected payoff would be:
$10g+0(1-g)$
Where g is the probability that the other person goes for the deer.
Whereas the payoff when I'm going for the hare:
$3g+3(1-g)$
Lumberdude #LeaveWolfAsHeIs
now im confused 
I'm sorry
would I need to do probabilities in my answers?
Maybe for the optimal strategy, but that hasn't been a question.
true because I have doubts that they would give me 13 marks for each of those
it seems too easy
Because the last question is not optimal strategy but strategy given that you can communicate
Ok, the payoff for the hare here is 3, that seems right!
The payoff for the deer is 10 times the probability the other player goes for the deer too. That means that that strategy is optimal if the chance that the other player goes for the deer is bigger than 3/10
Yeah idk how hard these are supposed to be?
they are for an undergraduate year 2 economics exam
it's a sample paper which replicates what the actual exam would be like
Aaaah, can you discuss these with a TA or the lectrurer?
ok I'll send an email to see what they say
should I ask if it includes probabilities?
yes, I'll ask
do you know how to solve these?
@tender sable
I'm no economist
I will look it up
Ok it seems like it is described by dy/dx or dx/dy
I think dy/dx
The derivative of U wrt y is 1/y, yes
Yes
ok so now we divide x and y
so 1 divided by 1/y
which is the same as 1 multiplied by y/1
so 1*y = y
so the answer is D?
Yes!
nice
Well done dude
thankyou
now for number 2
first lets differentiate
and let me find x
so make y = 0
that would be:
-2x + 2
nvm i'm confused
so far I got:
u(x) = -2x + 2
That's the du/dx?
I don't know how to go about that specific question haha
maybe if I -2
so it would be
2 = -2x
then divide by -2
so 2 divided by -2
= -1
so x would be -1?
I know MRS, this I do not know man
Maybe ask in general if there are any economists around
will do ๐
I will try reading into it
do you know about quantitative economics
Unfortunately I do not
this for example
check it out - I found another variation to part B ๐ฅ
this one has probabilites
would the answer to number 1 be P + P?
Hmm how did you get that answer?
ik it's wrong haha
Try to work it out by summing the two probabilities*payoff
If you go for a deer, what is the chance that the other person goes for a deer, what is the chance that they go for a hare, what is the average value you get
im confused sorry]
Ok I'll give you another example
Let's say I'm playing a game where I have to call heads or tails on a coin toss. If my choice wins I get $10, if I have it wrong I win nothing.
My expected payoff if I choose heads is:
p*10+(1-p)*0, where p= probability that the coin lands on heads
what does 1-p stand for?
and the 0
In my example yes
Yes, since there are only two options
It is the payoff for tails, given that I'm going for heads
in this example
It is the expected payout given that I chose heads
yes, makes sense
because you'll get nothing
if it doesn't land on heads
so in this case it would be:
P(10) + (1-P) * 0
that's the general equation?
so the expected payoff for Alonso going for deer
is P(10)?
or P(10) - (1-p)
Yes exactly
No the probability for the other person going for the deer should be the same