#Help

50 messages · Page 1 of 1 (latest)

golden ore
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Don't know how to answer this

small bridgeBOT
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ionic shale
golden ore
ionic shale
# golden ore I'm not sure

Okay well « ux »  denotes the partial derivative of u with respect to x and « uy » with respect to y

golden ore
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I see

ionic shale
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so basically ux is calculated by considering y a constant and differentiating only with respect to x

golden ore
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I need to work out ux and uy and then divide them together right?

ionic shale
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Yes

golden ore
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so if I make y = 0 to find x

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how do I work out the rest

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does that mean x is 1?

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ln(0) + x

ionic shale
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No x and y can be anything you just have to calculate the partial derivative

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For example if f(x,y)=x+y^2 then fx(x,y)= 1 and fy(x,y)=2y

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In each case you differentiate with respect to one of the two variables

golden ore
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ln(y) + x

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not sure how to differentiate it

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how do I find x and y?

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hello

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anyone

ionic shale
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The derivative of ln(x) is 1/x

golden ore
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HELPPP 😥

ionic shale
# golden ore i don't get it

Here you have u(x,y)=ln(y) +x so ux(x,y) denotes the partial derivative with respect to x so what is the derivative of x+ln(y) with respect to x? (ln(y) is a constant here because it doesn’t depend on x)

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uy(x,y) denotes the derivative with respect to y so you consider x a constant and y the variable

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Like I said before the derivative of ln(y) is 1/y

golden ore
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so ln(5) would be 1/5?

ionic shale
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But the derivative of ln(5) is 0 because it’s a constant

golden ore
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so if ln(y) = 1/y and x = 1, that means 1/1/y which is y?

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so is the answer D

ionic shale
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Yes

golden ore
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really?

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so the answer to that problem is D

ionic shale
ionic shale
ionic shale
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So fx(x,y)/fy(x,y)=1/(1/y)=y

golden ore
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can I give you another problem

golden ore
ionic shale
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Sure it’s your channel you can post if you want

golden ore
# golden ore

the best response for Alfonso would be to hunt for deer right?

ionic shale
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I’ll look at the problem tomorrow I’ve gotta go afk

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Im sorry

golden ore
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ok

ionic shale
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Good luck anyways

golden ore
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thanks for your help