#How do I solve for y? I know I should take logs but I don’t know how to proceed

33 messages · Page 1 of 1 (latest)

nocturne trout
wooden mulchBOT
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last totem
delicate iceBOT
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Omegabet_

nocturne trout
hardy ravenBOT
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@nocturne trout has given 1 rep to @last totem

nocturne trout
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@last totem does the quadratic formula work if the coefficient of x^2 is negative?

last totem
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you dont have an x^2

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but yes

nocturne trout
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X^2 is just an example

last totem
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obviously it does

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since the formula holds for any triple of (valid) coefficients

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the proof doesnt stipulate the coefficients must have certain properties, just that a isnt 0

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which.. duh lol

nocturne trout
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Alright

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@last totem how do I proceed?

last totem
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solve the quadratic

nocturne trout
last totem
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yeah, you didnt solve correctly...

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$1-u(u-2)=x\to 1-u^2+2u=x\to u^2-2u+(x-1)=0$

delicate iceBOT
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Omegabet_

last totem
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as you should recall from high school... you need a quadratic = 0 to use the quad formula

trail grove
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then u ln both sides

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and get y = ln(2 plusminus root (4-4(x-1))

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that should be the answer

trail grove
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ur supposed to treat

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x as a constant

last totem
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especially... 8 hours after