#Factoring Quadratics
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The algorithm is the same as for (1) and (2). For each variable you just pick its lowest power in all of the expressions to find the its factor in the GCD. Note that if a variable isn't present, its power is 0.
do you know the answer to 4
What did you get?
yes
For number 3: I found the gcf of all digits which was 3. Then I found the smallest variables/exponents , which were a and b and i got 3ab
3 and b are correct, but a is incorrect. What are the powers of a in each expression?
For number 4: I found the gcf of both which was 1 since 7 is a prime. Then I found smallest variables/ exponents which was only x^2 and y^3
since its not a, shouldnt it be a^2?
No.
Again, what are the powers of a in each of the three expressions?
2, 1 , and 0
Right. Which is the smallest?
0
so 12b is an imaginary a?
What do you mean?
the last expression is 12b so i thought that it was invisible since it is the power 0
is that correct?