What's a faster way to find the value of a?

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[floral bison]

use a^n + b^n = (a+b)(a^n-1 - a^n-1 b + a^n-2 b^2 - ... +- b^n-1)

or i guess 1 + root2 and 1-root2 are reciprocals of each other

ouh

they are reciprocals of each other

hey @wary vale

i found the trick

clear to this part?

i think i messed up

💀

yeah i messed up a minus symbol

but the trick is still the same

you'll get the idea

multiply these two

ill solve it with correct symbols real quick

1-sqrt(2) = -1/x

i forgot the symbol

just put 1+sqrt(2) in the denominator and rationalise it

youll see

ill solve it further for ya

no no no

just find

see

its easy

you'll get it when you see the solution

the x^n + 1/x^n is really easy to expand

from here

you could multiply the 3 and 4 power equaitions

[frosty salmon]

@loud star has given 1 rep to @floral bison

[floral bison]

same with powers exceeding 2000