#factorial
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Use a calculator
1!+2!+...+12! = 1 + 2*(1 + 3*(1 + ... *(1+12)...))
May be easier to calculate this way
522956313
Wrong
ru sure?
reduce it mod 100
Could you write few steps please?
actually we need to reduce them mod 1000
1!=1
2!=2
3!=6
4!=24
5!=120
6!=720
7!=4900+140=5040=40
8!=320
9!=2700+180=880
10!=8800=800
11!=8800=800
12!=8000+1600=600
adding them :
1+2+6+24+120+720+40+320+880+800+800+600=33+160+40+200+880=233+80=313
@south dune
Yes bro
so the number is XXXXXXXXXXXXX313
11!/2?

