#sketching complex

32 messages · Page 1 of 1 (latest)

tender dewBOT
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midnight salmon
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can you draw the line Im(z) - Re(z) = 1?

wary raft
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No …

midnight salmon
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that's y - x = 1 on a ordinary cartesian plane

wary raft
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I might be cooked

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Oh

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Would that solve my issue?

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And then shading the area within those 3 lines

midnight salmon
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yep

wary raft
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Really quickly, could you please give me some pointers (if you have time) on how I could attempt part b)?

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This is where I’m at right now

noble raven
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The vertical segment is rather straightforward, varying the imaginary part would making the graph of the exponential draw an arc centred at the origin

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The horizontal segment is also similar, should be a radial segment which, when extended, passes through the origin

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The toughest part is the remaining logarithmic spiral mapped from the upward sloping segment

wary raft
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How do you recognise how to transform the function in this way

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Are you take the exponent of the line?

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As z—>e^z

noble raven
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The function is the transform

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To be precise, I am taking the exponential of each point on the line segments

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Since the real parts of all points on a vertical line are the same, they are mapped to points of equal magnitude

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Similarly, the imaginary parts of all points on a horizontal line are the same, so they are mapped to points of equal angular argument

wary raft
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I'm sorry but im not too sure I understand. So the Im(z) and Re(z) stay the same?

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But the y-x=1 line is altered by the exponential?

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How would I sketch the remaining logarithmic spiral? Would that stem from the y-x=1 line?

sour pythonBOT
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ℝafain

midnight salmon
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try it out for specific points on the line (-1, pi/2 - 1 + pi/2 i, i, etc.)

wary raft
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What do you mean by try it out?

noble raven
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Map those specific points

wary raft
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Plot them on the graph?

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I'm not sure how to sketch this.