#Quadratic Functions

19 messages · Page 1 of 1 (latest)

river fractalBOT
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carmine bane
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try to make a draw

wild cloud
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thats where i get confused

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but i thought

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maybe we should use

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the equation : f(x) = a(x-x1)(x-x2)

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bc like

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ur T(6,-6) and ur x1 = 0 en x2= 12

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if i do all that i come out on

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f(x) = 1/6x**2 -2x

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but then when i try to do a en b

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i dont come out on square roots

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which the correction says you should

high sparrow
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As the position of the parabola doesn't matter, we can take one of its roots to be 0. So:
f(x) = ax(x - x0), 0 ≤ x ≤ x0
Then, you need two conditions:

  1. The second root is 12 away from the first.
  2. The minimum value is -6.
    That allows you to find a and x0. After that, in (b) you need to solve f(x) ≤ 3.
wild cloud
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okay u lowkey confused me

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@high sparrow

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the correction says the answer on a is 6v2

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whatever i do i dont come out on that