#Quadratic Functions
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try to make a draw
thats where i get confused
but i thought
maybe we should use
the equation : f(x) = a(x-x1)(x-x2)
bc like
ur T(6,-6) and ur x1 = 0 en x2= 12
if i do all that i come out on
f(x) = 1/6x**2 -2x
but then when i try to do a en b
i dont come out on square roots
which the correction says you should
As the position of the parabola doesn't matter, we can take one of its roots to be 0. So:
f(x) = ax(x - x0), 0 ≤ x ≤ x0
Then, you need two conditions:
- The second root is 12 away from the first.
- The minimum value is -6.
That allows you to find a and x0. After that, in (b) you need to solve f(x) ≤ 3.