trigonometry

[bleak blaze]

Could someone explain part b and c to me?

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[peak lodge]

(b). Note that ACB is an isosceles triangle. To see why that expression works, try drawing the height from C to AB.
(c). Just the definition of perimeter.

[bleak blaze]

What do you mean by “draw a height from C to AB)?

Like do you want me to divide the isosceles triangle in two halves?

[peak lodge]

Yes.

[pale nova]

Like a straight line

down to AB from C

[bleak blaze]

Yeah but how would that help me solve it?

[peak lodge]

You will get two congruent right triangles.

[bleak blaze]

How? Isn’t d shifted to the left?

[pale nova]

then use soh cah toa

[peak lodge]

It won't fall on D.

[bleak blaze]

Wait

Like this?

[pale nova]

Yes

[bleak blaze]

But but but

If I use the trig ratios here

[pale nova]

Then use soh cah toa to find the other angles and sides

[bleak blaze]

I won’t actually get the value of Ad

Will I?

[peak lodge]

You don't need AD, you need AB.

Well, at least, you need AB at the moment.

[bleak blaze]

The parent triangle isn’t a right angled triangle

[peak lodge]

After that you'll be able to find AD.

[bleak blaze]

Oh

Got it

lol

[pale nova]

No because we haven’t got the ratio to what the line AB is split into

[bleak blaze]

I thought we were dividing the triangle into two halves to find AD

But I got your point now

[peak lodge]

No. We find half of AB, then AB, and then AD.

[bleak blaze]

We gotta find Ab first

And then move to Ad

[pale nova]

Yes

[bleak blaze]

Yeah I got your point

Thanks

[pale nova]

Np