#Need help with rational function
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If x = -5/2 is a zero of g(x) = 0, that means g(-5/2) = 0. What equation do you get when you substitute x = -5/2?
g(-5/2) = (-5a/2)+5/(-5b/2)+c
Right. That needs to be equal to zero, so we get our first equation: -5a/2 + 5 = 0.
Now, the vertical asymptote.
We know that it must be x = 3. What does that tell us about the denominator?
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