#Help me understand this
23 messages · Page 1 of 1 (latest)
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try using the fact that 0, z1, z2, z1+z2 form a parallelogram
and z1-z2 is a diagonal of that parallelogram
that's fine, then try doing |z1+z2|^2=(z1+z2)(z1*+z2*)
and then find |z1-z2|^2 and compare
and use the fact that you know that |z1|=|z2|=1
well you are trying to find what |z1-z2| is
its a fixed value
but you are using an inequality
so that doesnt make sense
idk what your proof is
youd have to show me
actually wait yeah it shouldnt exist
because $$|z_1+z_2|^2=5=|z_1|^2+|z_2|^2+z_1z_2^{}+z_1^{}z_2$$ and so $z_1z_2^{}+z_1^{}z_2=3$, thus, $$|z_1-z_2|^2=|z_1|^2+|z_2|^2-z_1z_2^{}-z_1^{}z_2=1+1-3=-1$$ which is nonsense since $|z_1-z_2|^2\geq0$.
one eight seven
@keen solstice has given 1 rep to @verbal summit
yeah i didnt actually calculate it, just figured out the method to doing it
though triangle inequality is unconventional here since you want the expression
it happens to work because it doesnt exist
if it did exist, you wouldnt yield anything useful
the method i outlined above gives you the value of |z1-z2|
if it had an answer