#How can arc length start from this point?

53 messages · Page 1 of 1 (latest)

cosmic badger
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I understand the entire process of arc length reparametrization, but how can the point start from (0,8,0)? What t value would that even correspond to? I can't figure out the lower bound of the integration without knowing what t value that point corresponds to.

austere elmBOT
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vale vapor
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where is the curve defined, for starters

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you need that to calculate arc length

cosmic badger
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isn't it defined for all t?

vale vapor
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when you do arclength parametrization you'll have r(s) = (x(s), y(s), z(s)) and you will pick the parameter domain such that the "starting point" is (0,8,0)

vale vapor
cosmic badger
vale vapor
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parametrizations are always given such that r(t) = ... , where t in...

cosmic badger
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yes

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but can't i write the arc length as a function of t

vale vapor
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mhm, as usual integral 0^t r'(s)ds

cosmic badger
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yeah, but would it start at t = 0?

vale vapor
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yes

cosmic badger
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thats the thing t = 0 doesn't pass through the point (0, 8, 0)

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oh i see

vale vapor
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what do you think, is (0,8,0) on the curve in the first place?

cosmic badger
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hmm, i would say no

vale vapor
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t=0 seems forced and we have (0,-3,0) instead

cosmic badger
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yeah exactly

vale vapor
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so shift the curve

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but don't change the curve

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what do you do

cosmic badger
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ok i was thinking something like that

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shift 11 down the y axis?

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wouldnt z be up

vale vapor
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just shift 😄

cosmic badger
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ok so

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would i find the reparametrization

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if its something like

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this for example

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just add 11 to the second term would that work?

vale vapor
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that seems kind of arbitrary

cosmic badger
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ah sorry then where do i incorporate the shift

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how can you do arc length measured from a point thats not on the arc

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as you move along the arc do you just apply the distance formula again and again?

vale vapor
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in current form, the problem is illposed

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when you reparametrize, you do it starting from a fixed point t = a (implying, said point is on the curve)

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the point (0,8,0) is not on the curve, but the initial curve can be shifted such that this would be true

cosmic badger
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so can i change the function in the middle to 8t + 8?

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in that case the arc length formula would still be the same right

vale vapor
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yes, because when you differentiate, the constants disappear anyway

cosmic badger
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that honestly makes a lot of sense

cosmic badger
vale vapor
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the curve is still the same shape, it's just shifted

cosmic badger
cosmic badger
pastel prismBOT
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@cosmic badger has given 1 rep to @vale vapor

vale vapor
cosmic badger
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thank you man, I think I can piece it together now