#Small thing, but not sure how to solve this. :)

38 messages · Page 1 of 1 (latest)

toxic pawn
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Idk if it's clear, but it's sqrt2/2 divided by -sqrt2/2

soft sphinxBOT
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small fjord
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$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}$

barren cliffBOT
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Romans 12:19

small fjord
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or in this case, let $\frac{\sqrt{2}}{2}=u$ then we have $\frac{u}{-u}=-1$

barren cliffBOT
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Romans 12:19

toxic pawn
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so that comes out to be (sqrt2 * 2)/(2 * -sqrt2), would I cancel out the 2's? 🤔

small fjord
toxic pawn
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Oh. Then what am I left with?

small fjord
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-1

toxic pawn
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.. I'm doing something very wrong then

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my teacher got 3pi/4 sobbingTEArs

small fjord
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😭

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what are you solving

toxic pawn
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lemme get a pic xDD

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second one

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no idea how I solved the first one, but alas

small fjord
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it's simply asking for which angles between $0$ and $2\pi$ for which $\cos x=-\frac{\sqrt{2}}{2}$ and $\sin x=\frac{\sqrt{2}}{2}$

barren cliffBOT
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Romans 12:19

toxic pawn
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D: uh

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numbers, probably

small fjord
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do u know when sinx=sqrt(2)/2

toxic pawn
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I don't think so? I might've been taught but forgot

small fjord
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do u know what sin(pi/4) is

toxic pawn
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I wrote that down somewhere, hold on

small fjord
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oh wait5

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@whole lion u free rn to help this guy

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i gtg

toxic pawn
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oop np

whole lion
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One sec, let me move to my PC.

toxic pawn
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it's no biggie if you aren't available, for this specific one I can go to tutoring if needed in a few days :)

whole lion
toxic pawn
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yep :)

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I maybe know how to do everything else xD

whole lion
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Well, in any case, here's how you do it:
The points on a unit circle have coordinates (cos(θ), sin(θ)). So:

  1. Identify the signs of cos(θ) and sin(θ). That will determine the quarter that θ is in.
  2. Find tan(θ) = sin(θ)/cos(θ), then find θ in the quarter that you determined before.
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For example, in (I) we have:
cos(θ) = 1/2 > 0
sin(θ) = √(3)/2 > 0
So, the angle is in the first quarter. Next:
tan(θ) = √(3)
θ = π/3 + πn, n ∈ ℤ
The value lying in the first quarter is θ = π/3. If that's not immediately visible, we can solve a double inequality:
0 ≤ π/3 + πn ≤ π/2
0 ≤ 1/3 + n ≤ 1/2
-1/3 ≤ n ≤ 1/6
The integer solution is n = 0, so θ = π/3.

toxic pawn