#U-Substitution
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recall the derivative of exponential functions..
$\dv{x}a^x=\dv{x}e^{\ln(a)x}=\ln(a)e^{\ln(a)x}=a^x\ln(a)$
Omegabet_
Using this, I get to the point where du = (3^x)(ln3)(dx) but then how does that factor into making the function just u's? (3^x)(ln3) isn't anywhere in the question I don't think.
$u=3^x+4\implies\dd{u}=3^x\ln(3)\dd{x}\implies\int\frac{3^x}{\sqrt{3^x+4}}\dd{x}=\int\frac{1}{\sqrt{u}}\frac{1}{\ln(3)}\dd{u}$
Omegabet_
I get it now. Thanks for the help.
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