#prove it's linearly independent

41 messages · Page 1 of 1 (latest)

pseudo copper
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Let u and v be two linearly independent vectors. Let w = u + v and x = u - v. Prove that w and x are linearly independent.

i get to 0 = u (a+b) + v (a-b) and then i dont know what to do next or if this is even right

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uncut spade
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If u and v are linearly independent, what do a+b and a-b have to equal here?

pseudo copper
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is it a=b=0 so a-b=0 and a+b=0?

uncut spade
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Yep

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What happens when you add the two equations together

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Add $a-b = 0$ to $a + b = 0$

past horizonBOT
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MicMac

pseudo copper
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its zero

uncut spade
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On the right it's zero and on the left its (a-b) + (a+b), i.e., $(a - b) + (a + b) = 0$

past horizonBOT
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MicMac

uncut spade
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What does that simplify to?

pseudo copper
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2a?

uncut spade
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Yep

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So $2a = 0 \Rightarrow a = 0$

past horizonBOT
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MicMac

pseudo copper
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so i can just get rid of the u and v?

uncut spade
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Not exactly. Your goal should be to show that if $a(u + v) + b(u - v) = 0$, then $a = 0$ and $b = 0$.

past horizonBOT
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MicMac

uncut spade
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At this point, you're halfway there (more than that really) because we just saw that a must equal 0

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Now you just have to show that b = 0, which will be way easier than everything else so far.

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But if you mean that we don't have to do anything else with u and v in this problem, you're totally right

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All you gotta do is show that both a and b are zero

pseudo copper
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is it impossible for u or v to be 0

uncut spade
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Yeah, they can't be zero because the 0-vector is linearly dependent with everything

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Since u and v are linearly independent they both gotta be nonzero

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Like if $u$ were the zero vector, then $cu$ would equal zero for any real number c. But linear independence requires that to happen only when c is zero.

past horizonBOT
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MicMac

pseudo copper
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ohh i see

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but i dont understand how we take 0 = u(a+b) + v(a-b) and turn it into 0 = (a+b) + (a-b)

uncut spade
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So, you said back at the beginning that since u and v are linearly independent, then the numbers multiplying them here, a+b and a-b, have to be 0

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So you made two equations $a+b = 0$ and $a-b = 0$

past horizonBOT
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MicMac

uncut spade
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I suggested that you add the two equations together to eliminate b

pseudo copper
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ohhh sorry i get it now

uncut spade
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It's all good

pseudo copper
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thank u so much micmac

uncut spade
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Sure thing! Take care

pseudo copper
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u too

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