#How do I do the highlighted part of this question?
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Use the binomial distribution.
Also, considering that the number of successes for this event is a lot larger than the number of failures, it will be quicker to go from the opposite event.
how do i use the binomial distribution
Suppose we have n events, each having probability of success p.
Then the number of successes X follows a binomial distribution: X ~ Bin(n, p).
The PMF of X then is p(k) = C(n, k)p^k (1 - p)^(n - k), where C(n, k) = n!/(k! (n - k)!) is the binomial coefficient (number of combinations).
ah thank you, so putting n as 5 and p as 1/5 would give us the answer?
@bright comet has given 1 rep to @distant haven
No.
Well, we have 28 spins, so n = 28. p = 1/5, that's correct.
Our event is X ≥ 7, so it has 22 outcomes. Note, however, that the opposite event only has 7 outcomes. So, it will be quicker to calculate its probability first.
why 22 outcomes?
There are 22 integers from 7 to 28.
ah
wait but why is one faster than the other if you just plug numbers into a formula
Because in case of our event there will be 22 terms, but in case of the opposite event - only 7 terms.
so it's easier to do it the other way if you're not using a calculator?
Yes.
Besides, sometimes the number of outcomes of an event is infinite, but finite for the opposite event. Then it's pretty obvious that it's easier to work with the opposite event first.
ah got it ty
@bright comet has given 1 rep to @distant haven