Circles (Coordinate Geometry)

[slender shell]

Anyone please check where did I go wrong (correct answer is (3/2,11/2)

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[valid field]

No, that's not correct.
Start with the general equation of a circle:
(x - x0)^2 + (y - y0)^2 = R^2
Substitute the given coordinates into the equation. Then you'll have a system of equations in x0, y0 and R.

[high zodiac]

maybe that (y-2)^2 is y^2 - 4y + 4, not y^2 - 2y + 4

however this is not the easiest way to do this

using the perpendicular bisectors shoudl be much faster

[valid field]

Oh, that's true! And easy to generalize, too.

[slender shell]

how

[high zodiac]

well, find the midpoint of each line segment, and the slope

negative inverse it

solve for intersection of lines