#Calculus (integration)
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Try expressing G(x) in terms of F(t) first.
does that mean to just replace e^t^2 with F(t)?
would I split up the integral?
No, F(t) is the antiderivative of e^(t^2).
Is that what it means to be a primitive?
Yes. That term just isn't used as often now.
Using F(t), you can express G(x) using the fundamental theorem of calculus.
Sorry I'm a little lost here, perhaps due to terminology, an antiderivative is the same as taking the integral right?
The indefinite integral of f(x) is ∫(f(x)dx) = F(x) + C, where F(x) is the antiderivative of f(x).
By the fundamental theorem of calculus, the definite integral can be calculated as ∫(f(x)dx, a, b) = F(b) - F(a).
I think i understand! Thank you
@errant mason has given 1 rep to @torpid bone
Great! You're welcome 😁
Have I done it correctly?
Just wanted to check i've understood properly
No. The derivative of F(x) is f(x), but the derivative of, say, F(3x) is not f(3x).
You forgot about the chain rule.
ahha, thank you
@errant mason has given 1 rep to @torpid bone
So the derivative of F(3x) = 3f(3x)
Yes.
Tysm I don't know why it's taking my brain a long time to get around this
No worries! Take your time.
so it would be instead
3e^(9x^2) + 2e^(4x^2)
Minus, but yeah.
Whoops yup minus