Integration

[green sequoia]

Quick explanation

[rich sinew]

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1. Wait patiently for a helper to come along.
2. Once someone helps you, say thank you and close the thread with:

+close

3. Feel free to nominate the person for helper of the week in #helper-nominations
4. Do not ping the mods, unless someone is breaking the rules.
5. If you're happy with the help you got here, and the server overall, you can contribute financially as well:

[green sequoia]

Going from the 2nd to 3rd line

perhaps im not 100 percent sure on my integration but it seems they just forgot the x was at the beginning of the bracket?

or is there something im missing

can you just ignore it because of some rule or something?

Btw this is integration by inspection

[dapper quartz]

U substitution works

make the inside of the radical

$U=x^2-4$

[woeful orchid]

ビジヨン

[dapper quartz]

we then differentiate so that we get

$du=2xdx$

[woeful orchid]

ビジヨン

[dapper quartz]

solving for dx we get

$dx$ = $du\over 2x$

[woeful orchid]

ビジヨン

[dapper quartz]

$\int\frac{2x}{\sqrt(u)}\frac{du}{2x}$

so we get

$\int\frac{1}{\sqrt(u)}$ du

[woeful orchid]

ビジヨン

ビジヨン

[dapper quartz]

and now we solve this integral and then when we solve it, we can replace U with x^2-4