How to expand?

[noble marlin]

Lim 2(x+h)²
x -> 0
How we have to write that 2(x+h)²

[steady iris]

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[storm basin]

Are you evaluating the limit?

If so, then you actually don't have to expand the binomial, direct substitution can be directly used.

[quasi wind]

just substitute h=0, no need for all that

[noble marlin]

No actually I was trying to differentiate using first principle

The question was 2x²+3x

@quasi wind @storm basin

[quasi wind]

so you want to differentiate that function using definition of derivative?

[quasi wind]

this is h approaching 0 not x right?

[noble marlin]

Yes

[quasi wind]

youre on this step

[little perch]

wolfqz

[quasi wind]

well you got something wrong in the process because that is not the derivative of that function

[noble marlin]

Ignore my handwriting

[quasi wind]

,rotate

[noble marlin]

Is it ok this way?

I used [f(x+h) - f(x)]/h

This formula

[quasi wind]

just wait a few mins

ill see

[noble marlin]

Okk

[quasi wind]

ayo what happened after step 3

$\lim_{h\to 0} \frac{2h^2+4hx+3h}{h} = \lim_{h\to 0} \frac{h(2h+4x+3)}{h} = \lim_{h \to 0}2h+4x+3$

[little perch]

wolfqz

[quasi wind]

now we can just plug in the limit

@noble marlin

[noble marlin]

Thankssss got the answer

[stone nimbus]

@noble marlin has given 1 rep to @quasi wind

[noble marlin]

@quasi wind how to close this now?

[quasi wind]

+close

type that

[noble marlin]

Okk

+close