calc

[edgy nacelle]

Nope, we can evaluate this integral as-is

What we’re going to do is factor the denominator

This can be done by memory or noting that 1 + (-1)^3 = 0 and performing synthetic division

Let’s just consider the interior integral with respect to y without bounds first

We’ll get $\int \frac{1}{(y+1)(y^2 - y + 1)} \mathrm{d}y$

Do you know how to do partial fraction decomposition or do you need assistance here?

Well I messed up the factoring, it should be y+1

[lyric token]

(((((((Magma!)!)!)!)!)!)!)!

[edgy nacelle]

There we go

So we can’t use heavy side cover up method here because it doesn’t decompose into linear factors

No, not really

Did you solve it or what