#Quadratic Function
11 messages · Page 1 of 1 (latest)
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n^2 - n = (n-4)(an-4a + b + c)
n^2 - n = an^2 - 4an + bn + cn - 4an + 16a - 4b - 4c
n^2 - n = an^2 - 8an + bn + cn + 16a - 4b - 4c
n^2 - n = an^2 - n(8a - b - c) + (16a - 4b - 4c)
Compare LHS & RHS,
a = 1
8a - b - c = 1
8 - (b+c) = 1
b + c = 7
16a - 4b - 4c = 0
4a - (b+c) = 0
b + c = 4
No solution?
it isn't an equal sign
so what does it mean?
Sorry I'm not sure how to proceed further
ok