#Area
171 messages · Page 1 of 1 (latest)
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Yes I don't know where to begin
Do you know the formula for the sector of a circle?
Yeah exactly
And this should make sense because
Well
Wait sorry
$$\frac{\theta}{360^o} \times \pi r^2$$
PapaBread
Thats it I misread your formula
Oh ok
And this should make intuitive sense because like
What is the formula that I typed? Is it for an arc?
Yeah the arclength of a sector
Ok
All of these formulas work on the same basic principle though
The fraction of a whole circle a sector takes up * whatever
So like if the angle was 180° then obviously that would be half of the circle and therefore half the area
Why would it be half of the circle?
Or in your case if the angle is 33° then that makes up 33°/360°=9.167% about of the circle
Like imagine if you had 180° of a pizza
It would just be half of the pizza
Half of the amount of pizza (area), half of the length of the crust (arclength) etc
Oh right
So like if you break up the formula into two parts
What is the radius?
Yes
So this little thing
If you imagine the full circle that sector would make if you extende out whats the radius of that
Or if you just look at the little bit of the circle you can see
No its 55 cm
I thought you meant the radius of the unshaded part
Oh I see where you were going with that
Yeah no sorry I was just asking for the radius of the circle that makes up sector OAB
Since thats what part a wants
Ok, but the radius is half but isn't that part slanted?
The slant height would be shorter than the perpendicular height
Well this is a circle
So the distance from the center to any point on the circle is the same
Which is the definition of hte radius
I see
So now try applying the formula to all of the variables you have
So 33/360 x 3.14 x 55 x 55?
Mhm
It depends what your teacher wants
Youre gonna want to save this answer for later so for calculating purposes I wouldnt round it
Ok
Alright so now for part b
Do you kinda have an idea of what you need to do for this one?
Arc? 😄
It says area
The length for the two sides would be 12
But whay would be the width?
Do we use theta/360 x 2pir?
Well its not a rectangle
Youd need a special formula to find the area using the length and width of it
Theres an easier way using two sector area calculations
What do you use the formula of the arc for?
Imagine you had like
Im gonna keep going with the pizza analogy
If you had a big piece of pizza and you took a perfectly circular bite out of it
So the white is the pizza and the red is the bite
Yes
If the pizza originally had an area of 30 cm^2 and the bite had an area of 20 cm^2 how much pizza would be left in that outer segment
The crust
Yeah
So now you can do the same thing here
You have all the tools you need to find the original area of the pizza and the "bite"
Yeah so now you just need to calculate one more thing
Then you're set
The area of segment OCD
Yes
Yeah
I see, so that is why we could not round up 
Indeed
And also if you like fancy formulas you can also kinda condense all of this
Cause we have
$\frac{\theta}{360^o} \pi r_2^2 - \frac{\theta}{360^o} \pi r_1^2$
PapaBread
Then you can factor out all of that extra nasty stuff and youre left with just
$\frac{\theta}{360^o} \pi (r_2^2 - r_1^2)$
PapaBread
Oh ok
So anything like this
You just use the segment formula but instead of r you use r2-r1
But you dont really need to remember any of this its just a shortcut if you want
You can figure it out just using the one theta/360° * pi r^2 too
Why do you need AB?
It says to find the length of it for C
Oh
True true
I thought you were still on part b
Do you remember that formula you said earlier
1741.391667
,calc 33/360 * 2 * pi * 55
Result:
31.677725923697
Did you accidentally do it squared or sm?
I'll check
I used my phone calculator and I got your answer, but my scientific calculator is giving me a different one
Which means my previous answers could be wrong as well 
,calc 33/360 * pi * (67^2 - 55^2)
Result:
421.60173411175
Oh, I did it in the calculator and I got your answer, I must've done something wrong
Your answer is 3/360 * pi * 55^2 * 2 or something
Yes, I'll do your answer since I got the same answer on my phone calculator
Alright
You might wanna figure out whats wrong with your scientific calculator though
It is complicated to use in itself, before I get a whole number it first puts it in a fraction, then I have to press two other buttons to revert it back to a whole number, every single time 
It also has other mathematical operations like statistics, distribution, ratio, spreadsheet etc
I hate it
Oh, do you know how to get D? @junior plover
Wdym D
It says to calculate the radius of the circle formed by the arc AB
That should just be the same radius as the inner arc right
I think its 55
@strange crystal has given 1 rep to @junior plover
Yeah of course
@junior plover Hi, do you have time to help me with another question?
Sure
@junior plover
This is the same thing basically you're just subtracting two areas
@junior plover I'm doing it now and just realized I had the radius as 5 for the smaller circle and 10 for the bigger circle, is that right?
Yes
No
It's a semicircle and a rectangle
@junior plover would I do pir²/4
That's part of it yes


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