**2x^4** - **x^3** - **5x^2** + **3x** we can factor as **x(2x** - **3)(ax^ 2** + **bx** + **c)**De | Mathematics | Page 1

thorny haven Nov 18, 2023, 1:16 PM

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2x^4 - x^3 - 5x^2 + 3x we can factor as x(2x - 3)(ax^ 2 + bx + c)
Determine the values of a, b and c.

maiden nightBOT Nov 18, 2023, 1:16 PM

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thorny haven **2x^4** - **x^3** - **5x^2** + **3x** we can factor as **x(2x** - **3)(ax^ 2** ...

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winged ginkgo Nov 18, 2023, 1:17 PM

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oka\

thorny haven Nov 18, 2023, 1:17 PM

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yo

winged ginkgo Nov 18, 2023, 1:17 PM

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lets factorise $2x^4 - x^3 - 5x^2 + 3x$

exotic rapidsBOT Nov 18, 2023, 1:17 PM

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wolfqz

thorny haven Nov 18, 2023, 1:17 PM

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why?

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We don't need find what a, b and c is?

winged ginkgo Nov 18, 2023, 1:17 PM

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so that we can equate it

winged ginkgo Nov 18, 2023, 1:17 PM

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thorny haven We don't need find what a, b and c is?

ya and we are going to do that

thorny haven Nov 18, 2023, 1:17 PM

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ok

thorny haven Nov 18, 2023, 1:18 PM

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exotic rapids **wolfqz**

$(2x^2 - 3x) (ax^3 + bx^2 + cx)$ ?

exotic rapidsBOT Nov 18, 2023, 1:18 PM

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mathmastersupremenerdlord

winged ginkgo Nov 18, 2023, 1:19 PM

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bro what..

thorny haven Nov 18, 2023, 1:19 PM

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oh wait

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x(2x - 3)(ax^ 2 + bx + c)

winged ginkgo Nov 18, 2023, 1:19 PM

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dont think about a, b and c right now

thorny haven Nov 18, 2023, 1:19 PM

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ok

winged ginkgo Nov 18, 2023, 1:19 PM

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BRO

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we will worry about that later

thorny haven Nov 18, 2023, 1:19 PM

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ye

winged ginkgo Nov 18, 2023, 1:19 PM

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exotic rapids **wolfqz**

$x(2x^3-x^2-5x+3)$

exotic rapidsBOT Nov 18, 2023, 1:19 PM

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wolfqz

winged ginkgo Nov 18, 2023, 1:19 PM

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now you know how to factor cubics?

thorny haven Nov 18, 2023, 1:20 PM

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why put that on outside?

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I know how to do quadratic formula

winged ginkgo Nov 18, 2023, 1:20 PM

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cuz we are factorizing

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so we take it common

thorny haven Nov 18, 2023, 1:20 PM

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I know how to factor perfrct square

thorny haven Nov 18, 2023, 1:20 PM

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winged ginkgo now you know how to factor cubics?

no

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pls tell me

winged ginkgo Nov 18, 2023, 1:20 PM

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ok well

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basically you look at the factors of the constant term

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and hit and try if one of them is a zero of the cubic

thorny haven Nov 18, 2023, 1:21 PM

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winged ginkgo and hit and try if one of them is a zero of the cubic

nani

thorny haven Nov 18, 2023, 1:21 PM

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winged ginkgo basically you look at the factors of the constant term

2, -1, -5, 3?

winged ginkgo Nov 18, 2023, 1:22 PM

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3 is the constant term right

thorny haven Nov 18, 2023, 1:22 PM

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oh

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yea

winged ginkgo Nov 18, 2023, 1:22 PM

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its factors are 1,-1,3,-3

thorny haven Nov 18, 2023, 1:22 PM

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what?

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it's factors for what?

thorny haven Nov 18, 2023, 1:22 PM

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winged ginkgo its factors are 1,-1,3,-3

oh

winged ginkgo Nov 18, 2023, 1:22 PM

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wait

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you know polynomial long division?

thorny haven Nov 18, 2023, 1:22 PM

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Yes

winged ginkgo Nov 18, 2023, 1:22 PM

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oh..

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then its easy

thorny haven Nov 18, 2023, 1:22 PM

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I think I remember how to do properly

winged ginkgo Nov 18, 2023, 1:23 PM

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so

thorny haven Nov 18, 2023, 1:23 PM

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wai

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wait

winged ginkgo Nov 18, 2023, 1:23 PM

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$x(2x - 3)(ax^ 2 + bx + c)$

exotic rapidsBOT Nov 18, 2023, 1:23 PM

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wolfqz

thorny haven Nov 18, 2023, 1:23 PM

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divided by x(2x** - **3)?

winged ginkgo Nov 18, 2023, 1:23 PM

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thorny haven divided by x(2x** - **3)?

yeah exactly

thorny haven Nov 18, 2023, 1:23 PM

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divided by 1 of those?

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any of them right?

winged ginkgo Nov 18, 2023, 1:23 PM

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No

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both of those

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together

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divided by 2x^2 - 3x

thorny haven Nov 18, 2023, 1:24 PM

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yep

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but i mean

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can do this too?

winged ginkgo Nov 18, 2023, 1:24 PM

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huh

thorny haven Nov 18, 2023, 1:24 PM

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because these are 2 factors?

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lol im confused

winged ginkgo Nov 18, 2023, 1:24 PM

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i mean ya but u dont know a,b,c so it makes the problem harder

thorny haven Nov 18, 2023, 1:24 PM

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oh ye

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forgot about that

winged ginkgo Nov 18, 2023, 1:25 PM

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so just divide the polynomial by 2x^2 - 3x

thorny haven Nov 18, 2023, 1:26 PM

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+3x*

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@winged ginkgo

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Nah i did something wrong?

winged ginkgo Nov 18, 2023, 1:31 PM

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multiply by x^2

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not 2x^2

thorny haven Nov 18, 2023, 1:32 PM

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winged ginkgo not 2x^2

why

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2x^2 times 2x^4

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i mean divided

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oh

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thats x^2

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lol

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winged ginkgo Nov 18, 2023, 1:35 PM

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ya

thorny haven Nov 18, 2023, 1:35 PM

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what next?

winged ginkgo Nov 18, 2023, 1:35 PM

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+x ofc

thorny haven Nov 18, 2023, 1:35 PM

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+x ?

winged ginkgo Nov 18, 2023, 1:35 PM

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in the quotient

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thats how you do polynomial long division

thorny haven Nov 18, 2023, 1:36 PM

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quotitent?

winged ginkgo Nov 18, 2023, 1:36 PM

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because 2x^3 divided by 2x^2 is x

thorny haven Nov 18, 2023, 1:36 PM

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ye

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yep

winged ginkgo Nov 18, 2023, 1:36 PM

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so put x there

thorny haven Nov 18, 2023, 1:36 PM

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ik

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is that wrong?

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-2x^2 * 2x^2

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@winged ginkgo

winged ginkgo Nov 18, 2023, 1:42 PM

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what

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why the x^4 term

winged ginkgo Nov 18, 2023, 1:42 PM

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thorny haven -2x^2 * 2x^2

why did u do that

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the next step after +x was just multiplying by -1

thorny haven Nov 18, 2023, 1:42 PM

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?

winged ginkgo Nov 18, 2023, 1:42 PM

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No

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we dont do that

thorny haven Nov 18, 2023, 1:42 PM

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why

winged ginkgo Nov 18, 2023, 1:42 PM

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the degree is equal rn

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so we can multiply by a constant

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to make the degree go down

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here the constant is -1

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cuz 2x^2 divided by -2x^2 is -1

thorny haven Nov 18, 2023, 1:43 PM

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oh wait bro

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Multiple by -1?

thorny haven Nov 18, 2023, 1:44 PM

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winged ginkgo to make the degree go down

how?

winged ginkgo Nov 18, 2023, 1:46 PM

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Uh

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The same u did for the terms before

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doing it here

thorny haven Nov 18, 2023, 1:48 PM

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winged ginkgo The same u did for the terms before

?

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how do I add -1 to the polynomial division

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whjere to i Put it?

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@winged ginkgo

thorny haven Nov 18, 2023, 2:32 PM

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I got it

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x^2 + x-1

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what next?

winged ginkgo Nov 18, 2023, 6:07 PM

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Aha

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that is my equal to ax^2+bx+c

#**2x^4** - **x^3** - **5x^2** + **3x** we can factor as **x(2x** - **3)(ax^ 2** + **bx** + **c)**De

#2x^4 - x^3 - 5x^2 + 3x we can factor as x(2x - 3)(ax^ 2 + bx + c)De