#help beanie basic stuff calc

1130 messages · Page 2 of 2 (latest)

woeful glen
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np

tough summit
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oh

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alr

inner sand
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@woeful glen dms

tough summit
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brb

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back'\

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back

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u there?

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@woeful glen r u speaking

woeful glen
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$\derivative x f(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

regal basaltBOT
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wolfqz

tough summit
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cant see the stream btw

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idk if its cuz of my shit wifi

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or

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alr

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alr

woeful glen
tough summit
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secant line means graph of sec(x)

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right

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oh

woeful glen
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straight line that intersects the curve at two pts

tough summit
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yeah and what was h again

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like

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the displacement

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or

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the

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curved

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alr

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yeah'

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thats integration

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right

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oh

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okay

woeful glen
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$\derivative x x^2$

regal basaltBOT
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wolfqz

woeful glen
tough summit
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we just subtitute h = 0

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right

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right.

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mb

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yeah

woeful glen
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$\lim_{h\to 0}\frac{(x+h)^2 - x^2}{h}$

$\lim_{h\to 0} \frac{x^2+2xh+h^2-x^2}{h}$

tough summit
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h+2x?

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oh and how do we find lim of that

woeful glen
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just plug h=0

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as no more h in denominator

tough summit
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yeah alr so the final ans

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is 2x

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right

woeful glen
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Yeah

tough summit
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alr

woeful glen
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that is the derivative of x^2

tough summit
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alr

woeful glen
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now derivative at a point

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x=a

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2a

tough summit
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okay

woeful glen
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$\derivative x (ax^n+bx^{n-1}) = \derivative x ax^n + \derivative x bx^{n-1}$

regal basaltBOT
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wolfqz

tough summit
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alright

woeful glen
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$\derivative x (x^2+2x+1)$ at $x=5$

regal basaltBOT
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wolfqz

tough summit
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12

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damn i know calc

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now

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big boy stuff fr

woeful glen
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yeah!!

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real

last sigilBOT
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Shut the fuck up
tough summit
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how tf do u create questions

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arent u in 10th

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oh

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i thoguht u were

woeful glen
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$\derivative x \sin x$

regal basaltBOT
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wolfqz

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wolfqz

tough summit
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thanks

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no clue man

woeful glen
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$\lim_{h \to 0} \frac{\sin(x+h)-\sin(x)}{h}$

regal basaltBOT
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wolfqz

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wolfqz

tough summit
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yeah

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i got till

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here

woeful glen
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now

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we do something tricky stuff

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$\lim_{h \to 0} \frac{\sin(x)\cos(h) - \sin(x) +\sin(h)\cos(x)}{h}$

regal basaltBOT
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wolfqz

tough summit
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u take it common?

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i did that

woeful glen
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$\lim_{h \to 0} \frac{-\sin(x)(1-\cos(h))}{h} + \frac{\sin(h)\cos(x)}{h}$

tough summit
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wait

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isnt it

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cos(h) -1

regal basaltBOT
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wolfqz

tough summit
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oh

woeful glen
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$1-\cos(h) = 2\sin^2\frac{h}{2}$

regal basaltBOT
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wolfqz

woeful glen
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$\cosaddition$

regal basaltBOT
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wolfqz

woeful glen
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$\cos^2x - \sin^2x = 1-\sin^2x-\sin^2x = 1-2\sin^2x = \cos(2x)$

regal basaltBOT
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wolfqz

woeful glen
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$x = \frac{h}{2}$

$1-2\sin^2 \frac{h}{2} = \cos h$

regal basaltBOT
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wolfqz

woeful glen
woeful glen
# regal basalt **wolfqz**

$\lim_{h \to 0} \frac{-2\sin(x) \sin^2\frac{h}{2}}{h} + \frac{\sin(h)\cos(x)}{h}$

$\lim_{h \to 0} \frac{-2\sin(x) \sin^2\frac{h}{2}}{h} + \lim_{h \to 0} \frac{\sin(h)\cos(x)}{h}$

$-2\sin(x) \lim_{h \to 0} \frac{\sin^2 \frac{h}{2}}{h}+ \cos(x)\lim_{h \to 0} \frac{\sin(h)}{h}$

regal basaltBOT
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wolfqz

woeful glen
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$g(x) \leq f(x) \leq h(x)$\*

$\lim_{x \to a} g(x) = \lim_{x \to a} h(x) =L$

then $\lim_{x \to a} f(x) = L$

regal basaltBOT
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wolfqz

woeful glen
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$\cos^2x \leq \frac{\sin x}{x} \leq 1$

regal basaltBOT
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wolfqz

woeful glen
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^ can be proved using sectors and stuff

tough summit
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alr

woeful glen
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$\lim_{x \to 0} \cos^2 x = 1$

regal basaltBOT
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wolfqz

woeful glen
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$\lim_{x \to 0} 1 = 1$

regal basaltBOT
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wolfqz

tough summit
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so that limit is also 1

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sin x/x

woeful glen
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Yeah

tough summit
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okay

woeful glen
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$-2\sin(x) \lim_{h \to 0} \frac{\sin^2 \frac h2}{h} + \cos(x)$

regal basaltBOT
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wolfqz

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wolfqz

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wolfqz

woeful glen
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$-\sin(x) \lim_{h \to 0} \frac{\sin \frac h2}{\frac h2} \times \sin(0) + \cos(x)$

regal basaltBOT
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wolfqz

woeful glen
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$0+\cos(x) = \cos(x)$